Helpp please.... random multiple choice questions.?

A precipitate will form when an aqueous solution on lead (II) nitrate is added to aqueous solution of which of the following?


a. Mg(NO3)2 b. NH4CH3CO2 c. NaNO3 d. KNO3 e.NaCl





Which equation below best represents the balanced, net ionic equation for the reaction of a dilute solution of calcium hydroxide with a solution of hydrochloric acid?


a. Ca2+ (aq) + 2Cl1- (aq) -%26gt; CaCl2 (s)


b. Ca2+ (aq) + 2Cl1- (aq) -%26gt; CaCl2 (aq)


c. 2OH1- (aq) +2Cl1- (aq) -%26gt; H2O (L) + OCl2 (aq)


d. Ca(OH)2 (aq) + 2Cl1- (aq) -%26gt; CaCl2 (s) +2OH 1- (aq)


e. OH 1- (aq) + H1+ (aq) -%26gt; H2O (L)





Consider the equation: I1- (aq) + ClO1- (aq) -%26gt; IO1- (aq) + Cl1- (aq). The oxidizing agent is....


a. I1- b. ClO1- c. IO1- d. Cl1- e.H2O





The reducing agent (if any) in the following equation is...


2Mg (s) + TiCl4 (L) -%26gt; Ti(s) + 2MgCl2 (s)


a. Mg(s) b. TiCl4 (L) c.Ti(s) d. MgCl2(s) e.not a redox reaction





last one... =]





how many militers of 0.123M NaOH solution contain 25.0g of NaOH?








thanks.

Helpp please.... random multiple choice questions.?
e. NaCl (you make PbCl2)





e. This is an acid-base reaction and the Ca+2 and Cl- ions have no part.





b. The oxidizing agent is reduced in the reaction





a. The reducing agent is oxidized





25 g of NaOH is how many moles? Divide by the molecular weight (it's about 30 g/mole). Now divide this answer (in moles) by the molarity (in moles/liter) to get the volume. This will be a number about 6.8 L (but you'll want to check my math and report it to the proper number of significant figures)
Reply:E. says dilute Ca(OH)2. So OH- + H+





What is being oxidized? iodine-1 to +1(IO-) (loses 2e-) so the other compound ClO- must be oxidizing agent (removes e-), lets see%26gt; 1+ to 1- ans B)





What is being reduced? (gain e-) Not the Mg that is losing e- (oxidized to Mg2+) The TiCl4 gains, reduced to Ti


Since the TiCl4 is reduced, the reducing agent is Mg(s)





Molarity = moles / vol liter,


mol NaOH = mass / Mr





Therefore: (Mr/ mass) x Molarity = vol in litres





I'm sure you can work out the rest.