In a box of 9 batteries, 7 are dead. You choose two batteries at random from the box.
Let the random variable X be the number of good batteries you get. Find the expected value of X.
A. = 0.44
B. = 0.25
C. = 0.56
D. = 0.88
E. = 1.56
Find the expected value of the random variable.?
P(G) = 2/9
P(B) = 7/9
E(X) = ∑ xp
= 0*(7/9)(7/9) + 1*2*(2/9)(7/9) + 2(2/9)(2/9)
= 28/81 + 8/81
= 36/81
= 0.444
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