A mother has two babies:  Jack and Jill.  Once she puts them both to sleep, Jack will stay asleep for T hours, where
 
fT(t) = (K_1)λe^(-λt) for 0 ≤ t ≤ M,    0 otherwise
 
Jill will stay asleep for S hours, where
 
 fS(s) = K_2μe^(-μt) for 0 ≤ s ≤ M,    0 otherwise
 
We also assume that S and T are independent.
 
a.) Find the constants K_1, K_2 in terms of λ, μ, and M
 
b.) The mother has just put both babies to sleep.  What is the probability that she will have a break of at least tq hours before a baby wakes up?
 
c.) On a good day, jack's sleeping time distribution (given above) has λ = 1.  On a bad day, λ = 3.  Jack is three times as likely to have a good day than a bad day.  Also, the maximum time Jack will sleep on either type of day is 8 hours.  On a random day, what is the probability that Jack will sleep 2 hours or more after being put to bed?
Multiple Continuous Random Variables?
a) integral from 0 to M is equal to 1 so integrate w.r.t. t and solve for K_1 and K_2
b) integrate to find F(X) for both babies... 1 - F(X) = P(x %26gt; X) so insert tq in as X and multiply the two together as you assume the babies sleep independent of one another.
c. integrate Jack's function insert the lambdas and then t=2. then since Jack is 3 times as likely to have a good day P(Good) = 3/4 and P(Bad) = 1/4. But remember you have to do it like b) where you do 1-F(X)
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